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13n^2+793n-1794=0
a = 13; b = 793; c = -1794;
Δ = b2-4ac
Δ = 7932-4·13·(-1794)
Δ = 722137
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{722137}=\sqrt{169*4273}=\sqrt{169}*\sqrt{4273}=13\sqrt{4273}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(793)-13\sqrt{4273}}{2*13}=\frac{-793-13\sqrt{4273}}{26} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(793)+13\sqrt{4273}}{2*13}=\frac{-793+13\sqrt{4273}}{26} $
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